Kimia Q. kimia Terlampir !!​

baileyabernathyulv – April 06, 2023

Q. kimia

Terlampir !!


​

DIket:

dHf CH3OH = -238,6 kJ/mol

dHf CO2 = -393,5 kJ/mol

dHf H2O = -286 kJ/mol

Dit:

a. dHc

b. Q pembakaran 8 g CH3OH

Jawab:

a. 2 CH3OH(l) + 3 O2(g) -> 2 CO2(g) + 4 H2O(g)

Maka

dHc = dHf kanan - dHf kiri

= (4 dHf H2O + 2 dHf CO2) - 2 dHf CH3OH

= [4(-286) + 2(-393,5)] - 2(-238,6)

= -1931 + 477,2

= -1453,8 kJ/mol

b.  n CH3OH = g/Mr

= 8/32

= 0,25 mol

Qc = - dHc x n

= - (-1453,8 kJ/mol) 0,25 mol

= 363,45 kJ

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